1-9/x-3=-54/x^2-9

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Solution for 1-9/x-3=-54/x^2-9 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

1-(9/x)-3 = -54/(x^2)-9 // + -54/(x^2)-9

1-(9/x)-(-54/(x^2))-3+9 = 0

54*x^-2-9*x^-1-3+1+9 = 0

54*x^-2-9*x^-1+7 = 0

t_1 = x^-1

54*t_1^2-9*t_1^1+7 = 0

54*t_1^2-9*t_1+7 = 0

DELTA = (-9)^2-(4*7*54)

DELTA = -1431

DELTA < 0

x belongs to the empty set

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